Saturday, September 21, 2019
Pythagoras Theorem and Financial polynomials Essay Example for Free
 Pythagoras Theorem and Financial polynomials Essay  Pythagoras Theorem and Financial polynomials  Introduction  à   à   à   à   à   à   Ahmed and Vanessa have interest in locating a treasure, which is buried. It is my responsibility to help the two locate it. First, I will help them locate it by the use of Pythagorean quadratic. As per Ahmedââ¬â¢s half, the treasure is buried in the desert (2x + 6) paces form the Castle Rock while as per Vanessaââ¬â¢s half she has to walk (x) paces to the north then walk (2x + 4) paces to the east.         According to the Pythagorean theorem, every right angled triangle with length (a) and (b) as well as a hypotenuse (c), has a relationship of (a2 + b2 = c2) (Larson  Hostetler, 2009).  à   à   à   à   à   à   In Ahmed and Vanessaââ¬â¢s case, I will let a=x, b =2x+4 and then c=2x+6. To follow, will be my efforts to put the measurements above into the real Pythagoras theorem equation as follows:  X2+ (2x+4)2=(2x+6)2 this is the equation formed out of the Pythagoras Theorem  X2+42+16x+16 = 42+ 24x+36 are the binomials squared  x2  42 on both sides can be subtracted out.  X2+16x+16 = 24x +36 subtract 16x from both sides  X2+16 = 8x+36 now subtract 36 from both sides  X2-20 = 8x  X2-8x-20=0 I will use to solve the function by factoring using the zero factor.  (x-) (x+) the coefficient of x2  Application and selection from the following (-2, 10: -10,2: -5,4; -4, -5)  In this case, it seems that I am going to use -10 and 2 is as per how the expression looks like this (x-10)(x+2)=0  X-10=0 or x+2=0 creation of a complex equation  x=10 or x=-2 these are the two probable resolutions to this equation.  à   à   à   à   à   à   One of the two calculated solutions is an extraneous solutions, as it do not work with such sceneries. The remaining solution I only have is (X=10) as the number of paces Ahmed and Vanessa have to accomplish to find the lost treasure. As a result the treasure is 10 paces to the north 2x+4 connect the 10, now its 2(10)+4=24 paces to the east of Castle Rock, or 2x+6= 2(10)+6=26 paces from Castle Rock.  Financial polynomial  à   à   à   à   à   à   For the case of financial polynomials, I have first to write the polynomial without the parenthesis. Following the above, I have to solve for p= 2000 + r = 10% for part A and then solve for p= $5670 + r = 3.5% for part B, without the parenthesis as follows:  P + P r + P r2/4 (the original polynomial) to reach this I followed the following steps:  (1 + r/2)2 This is because it looks as if it is foil  P(1 + r/2)  P (1+r/2)(1+r/2) After the two equations I combine like terms. Because I am multiplying by 2 on r/2, it cancels out both 2ââ¬â¢s and I then get left with is r as follows;  P(1+ r/2 + r/2 + r2/4)  P(1 + 2(r/2) + r2/4)  I then write in descending order (P + Pr + Pr2)  To solve for P=2000 and r=10% the following follows;  P + Pr + Pr2/4  2000 + 2000 Ãâ"(0.10) +2000Ãâ" 0.1024  2000 + 200 + 5 = $2205  P(1+ r/2)2  2000Ãâ"( 1 + .10)2  2000Ãâ"(1.05)2  2000Ãâ"( 1.1025) = $2205  For part B I will solve for P=5670 and r= 3.5%  P + Pr + P Ãâ"(r2/4)  5670 + 5670Ãâ" (0.035) + 5670 Ãâ" 0.0352  5670 + 198.45 + 1.7364375 = 5870.1864375  This is approximately ($5870.19)  The problem 70 on page 311 has the following steps;  (-93 + 32 ââ¬â 15x) à · (-3x)  The Dividend is (-93 + 32 ââ¬â 15x), and the Divisor is (-3x).  The Dividend is (-93 + 32 ââ¬â 15x), and the Divisor is (-3x).  -93 + 32  15x  -3xAfter I divide -9 by -3 which equals +3. The x on the bottom cancels the x from the top.  -93 + 32 ââ¬â 15x  -3x -3x -3x  -9* x*x* x  I am now left with 32 for the first part of the polynomial.  -3 * x  -9*x *x * x  -3 * x  I first divide 3 by -3, which equals -1 and the x from the bottom cancels out one of the xââ¬â¢s from the top.  -93 + 32 ââ¬â 15x  -3x -3x -3x  3 *x *x  At this point I am left with -1x, which simplifies to just ââ¬âx, as the second part of the polynomial.  Then  -3 *x  3 *x * x  -3 * x  Then I divide -15 by -3, which equals positive 5, and the x on the bottom cancels out the x on the top, so you do not have any xââ¬â¢s to carry onto the answer of the equation.  -93 + 32 ââ¬â 15x  -3x -3x -3x  -15 *x  At this point I am left with only 5 for the last part of the polynomial, and the answer is  32 ââ¬â x + 5.  -3 * x  -15 * x  -3 * x  à   à   à   à   à   à   The negative sign from the -3 x changes the plus sign in the equation to a minus sign, it changes the minus sign to a plus sign in the final answer, and the equation is in Descending order.  Reference  Larson, R.,  Hostetler, R. P. (2009). Elementary and intermediate algebra. Boston, Mass: Houghton Mifflin  Source document    
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